浅谈MySQL数据库中如何解决分组统计的问题_MySQL数据库_黑客防线网安服务器维护基地--Powered by WWW.RONGSEN.COM.CN

浅谈MySQL数据库数据库中如何解决分组统计的问题

作者:黑客防线网安MYSQL维护基地 来源:黑客防线网安MYSQL维护基地 浏览次数:0

本篇关键词:统计问题分组解决
黑客防线网安网讯:首先准备四张表A、B、C、D, --------------------------------     A      | B  | C   | D     a   b   |   a   c   |   a   d   |   d   e     1   1   |   1   1   |   1   A   | ...

首先准备四张表A、B、C、D

--------------------------------    
A      | B  | C   | D    
a   b   |   a   c   |   a   d   |   d   e    
1   1   |   1   1   |   1   A   |   A   1    
2   2   |   1   3   |   2   B   |   B   2    
3   4   |   1   4   |   3   C   |   C   3    
4   6   |   2   1   |   4   D   |   D   4    
--------------------------------

  下面我们需要用一条sql语句将A表所有的列B表对与A表a字段相关联的列求count,通过C表,将D表与A表关联起来,得到的结果如下:

1   1   3   1    
2   2   1   2    
3   4   0   3    
4   6   0   4

  Mysql语句解决:

select A.a,A.b,IFNULL(c,0) as c,D.a
from (select 1 as a,2 as b union all
select 2 as a,2 as b union all
select 3 as a,4 as b union all
select 4 as a,6 as b) as A
left outer join    
(select a,count(a) as c from(
select 1 as a,3 as c union all
select 1 as a,3 as c union all
select 1 as a,3 as c union all
select 2 as a,3 as c ) B group by a) as B
on A.a=B.a
join
(select 1 as a,'A' as d union all
select 2 as a,'B' as d union all
select 3 as a,'C' as d union all
select 4 as a,'D' as d ) as C
on A.a=C.a
join(select 1 as a,'A' as d union all
select 2 as a,'B' as d union all
select 3 as a,'C' as d union all
select 4 as a,'D' as d ) as D
on D.d=C.d

    黑客防线网安服务器维护方案本篇连接:http://www.rongsen.com.cn/show-8073-1.html
网站维护教程更新时间:2012-03-20 04:48:19  【打印此页】  【关闭
我要申请本站N点 | 黑客防线官网 |  
专业服务器维护及网站维护手工安全搭建环境,网站安全加固服务。黑客防线网安服务器维护基地招商进行中!QQ:29769479

footer  footer  footer  footer